| 1 |
What is the primary advantage of using cup lump rubber (CLR) in cold mix asphalt (CMA)?
|
Improves functional properties of the asphalt |
|
CLR can enhance the performance characteristics of the asphalt, such as its durability, flexibility, and resistance to cracking and deformation. |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 2 |
Which property of CMA is significantly improved by the addition of CLR?
|
Tensile strength |
|
CLR enhances the tensile strength and overall performance of CMA by improving its flexibility and resistance to cracking. |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 3 |
If the tensile strength of CMA increases by 26% due to the addition of CLR and the original tensile strength was 5 MPa, what is the new tensile strength?
|
6.3 MPa |
|
Increase=Original Tensile Strength×Percentage Increase
New Tensile Strength=Original Tensile Strength+Increase |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 4 |
Given that the rut depth decreases by 70% when CLR is added to CMA and the original rut depth was 10 mm, what is the new rut depth?
|
3 mm |
|
Decrease=Original Rut Depth×Percentage Decrease
New Rut Depth=Original Rut Depth−Decrease
|
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 5 |
If the CMA with CLR has a TSR (Tensile Strength Ratio) value of 104% and the minimum requirement is 80%, by what percentage does the TSR exceed the requirement?
|
30% |
|
Difference=TSR Value−Minimum Requirement
|
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 6 |
What is the potential increase in moisture damage resistance for CMA-CR compared to conventional CMA if the improvement is 12%?
|
12% |
|
If the improvement in moisture damage resistance for CMA-CR compared to conventional CMA is 12%, then the potential increase is 12%. |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 7 |
If the shear resistance of CLR-modified CMA increases due to the membrane effect, which physical property is most directly influenced?
|
Elasticity |
|
The most directly influenced physical property when shear resistance increases due to the membrane effect in CLR-modified CMA is Elasticity. |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 8 |
The viscosity of CLR-modified bitumen at 135°C is 1.16 Pa·s. If the shear rate is 50 s^-1, what is the shear stress?
|
58 Pa |
|
Shear Stress=Viscosity×Shear Rate |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 9 |
If the mass loss in the Cantabro test for CMA-CR is 14.6% and the maximum accepted limit is 20%, by how much does CMA-CR fall below the limit?
|
5.4% |
|
Maximum accepted limit = 20%
Mass loss of CMA-CR = 14.6%
Difference = 20% - 14.6% = 5.4% |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 10 |
What is the significance of using cup lump rubber in the context of environmental sustainability?
|
It helps in lowering carbon emissions during production. |
|
contributing to a reduction in the environmental impact of asphalt production by recycling waste materials and reducing the need for new raw materials. |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 11 |
What is one of the emerging trends affecting China's oil and gas pipeline development strategies?
|
Digitization |
|
One of the emerging trends affecting China's oil and gas pipeline development strategies is digitization. |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 12 |
What is the proportion of natural gas pipelines in the total length of long-distance oil and gas pipelines in China as of 2022?
|
50% |
|
As of 2022, the proportion of natural gas pipelines in the total length of long-distance oil and gas pipelines in China is approximately 50% |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 13 |
If the total length of long-distance oil and gas pipelines in China is 180,000 km, how many kilometers are dedicated to natural gas pipelines?
|
126,000 km |
|
Length of natural gas pipelines=0.70×180,000km=126,000km |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 14 |
According to the article, if the target length for oil and gas pipelines is 210,000 km by 2025, how many kilometers need to be constructed from the 2022 total?
|
30,000 km |
|
Kilometers to be constructed=210,000km−180,000km=30,000km
|
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 15 |
If the failure rate of oil and gas pipelines in Europe is 0.29 per year per hundred kilometers, what is the failure rate per year for a pipeline network of 1,000 kilometers?
|
2.9 failures |
|
Failure rate per year=0.29×10=2.9 |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 16 |
What is one of the main causes of oil and gas pipeline failures in China according to the article?
|
Oil theft through drilling |
|
One of the main causes of oil and gas pipeline failures in China, according to the article, is oil theft through drilling |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 17 |
Assuming the failure rate in the United States is 0.14 per year per hundred kilometers, calculate the expected number of failures per year for a 1,500 kilometers pipeline network.
|
2.1 failures |
|
the expected number of failures per year for a 1,500 kilometers pipeline network is 2.1 failures. |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 18 |
If a pipeline defect inspection technology improves detection efficiency by 25% and the current detection efficiency is 80%, what will be the new detection efficiency?
|
100% |
|
Determine 25% of the current detection efficiency:
25
%
of
80
%
=
0.25
×
80
%
=
20
%
25% of 80%=0.25×80%=20%
Add this improvement to the current detection efficiency:
New detection efficiency=80%+20%=100%New detection efficiency=80%+20%=100%
|
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 19 |
If a vibration signal monitoring system faces a 15% reduction in noise levels due to a new technology and the original noise level was 200 units, what is the new noise level?
|
170 units |
|
Subtract the reduction from the original noise level:
New noise level
=
200
units
−
30
units
=
170
units
New noise level=200 units−30 units=170 units
|
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|
| 20 |
For a hydrogen pipeline with an embrittlement rate of 0.05% per year, calculate the total embrittlement after 10 years.
|
0.5% |
|
Total embrittlement=(1.0005)
10
−1≈0.005 or 0.5% |
- |
7 |
-.50
-.25
+.25
เต็ม
0
-35%
+30%
+35%
|