| 1 |
What is the primary role of transition metal ion catalysts in the catalytic ozonation process for nanoplastic removal?
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To facilitate the decomposition of O3 and generate active free radicals |
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transition metal ions and metal oxides are commonly employed as catalysts to enhance O3 transformation
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https://www.sciencedirect.com/science/article/pii/S2666821124000395
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| 2 |
According to the article, what was the observed effect of using Co2+ at 1 mM on the mineralization rate of polystyrene nanoplastics during ozonation?
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Decreased mineralization rate by 70% |
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in the presence of Co2+ (1 mM), the highest PSNPs ozonation performance was achieved, decreasing the turbidity up to 65 % and achieving 70 % of mineralization in the same ozonation time.
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https://www.sciencedirect.com/science/article/pii/S2666821124000395
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| 3 |
In the context of nanoplastics removal, what does the scavenger experiment with methanol demonstrate about the catalytic ozonation process?
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Methanol interferes with the generation of hydroxyl radicals |
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methanol effectively scavenges the hydroxyl radicals and reduces the efficiency of nanoplastics degradation
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https://www.sciencedirect.com/science/article/pii/S2666821124000395
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| 4 |
If the initial concentration of nanoplastics is 20 mg/L and the catalytic ozonation achieves a 70% mineralization rate, what is the concentration of remaining nanoplastics?
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6 mg/L |
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if we have Initial concentration of nanoplastics = 20 mg/L
and Mineralization rate = 70%
then 20 mg/L - (20 mg/L x 0.70) = 6 mg/L
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Remaining nanoplastics = Initial concentration - (Initial concentration x Mineralization rate)
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| 5 |
Given an ozone flow rate of 0.5 NL/min and an ozonation time of 120 minutes, how much ozone (in grams) has been used if the ozone concentration is 10 mg/NL?
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0.6 grams |
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Total ozone used = 0.5 NL/min x 120 min x 10 mg/NL then Total ozone used = 600 mg
and next mg to g by 1 g = 1000 mg that mean 600 mg / 1000 mg = _____ g
600/1000 = 0.6 g
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Total ozone used = Ozone flow rate x Ozonation time x Ozone concentration
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| 6 |
If reducing the turbidity of water by catalytic ozonation with Co2+ from 100 NTU to 35 NTU represents a 65% reduction, what was the original turbidity?
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100 NTU |
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if ( X ) is the original turbidity before reduction.
then 65% of X = X - 35 NTU
0.65X = X - 35 NTU
0.65X + 35 NTU = X
=100 NTU
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Turbidity reduction = Original turbidity - Final turbidity
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| 7 |
What is a major benefit of catalytic ozonation over single ozonation in water treatment?
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It provides higher mineralization rates |
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It more effective and it use less Ozone
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https://www.sciencedirect.com/science/article/pii/S2666821124000395
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| 8 |
Which of the following is NOT a transition metal ion used as a catalyst in the study?
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Ca2+ |
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Ca2+ is NOT a transition metal ion.
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Reference from : periodic table
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| 9 |
What environmental issue does the removal of nanoplastics address?
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Reduction of water pollution |
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Nanoplastics often found in the water so it a water Pollution and it bad for aquatic ecosystems too
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https://www.sciencedirect.com/science/article/pii/S2666821124000395
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| 10 |
What analytical technique is NOT mentioned as used for monitoring the degradation of nanoplastics?
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UV-Vis Spectrophotometry |
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UV-Vis Spectrophotometry
is commonly used for analyzing the absorption or transmission of light not Nanoplastics
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https://en.wikipedia.org/wiki/Ultraviolet–visible_spectroscopy
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| 11 |
What effect does the melt fiber spinning system have on the crystallinity of PET fibers?
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It decreases the crystallinity to less than 10%. |
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It Decreases The Crystallinity
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https://www.sciencedirect.com/science/article/pii/S2666821124000425
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| 12 |
What role does the spooling speed play in the fiber spinning system described in the article?
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Higher spooling speeds lead to lower crystallinity and smaller fiber diameters. |
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https://www.sciencedirect.com/science/article/pii/S2666821124000425
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| 13 |
According to the article, what was the impact of using the LCC-ICCG enzyme on PET depolymerization?
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It significantly increased the monomer release from PET. |
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https://www.sciencedirect.com/science/article/pii/S2666821124000425
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| 14 |
If the initial mass of PET before enzymatic treatment in a bioreactor was 500 grams and 96.9% mass was lost due to depolymerization, what is the final mass of PET?
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15.5 grams |
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first find Mass lost = 500 grams * 0.969 = 484.5 grams
then Calculate the final mass of PET by using Calculator and Final mass = Initial mass - Mass lost
Final mass = 500 grams - 484.5 grams = 15.5 grams
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Calculator and Final mass = Initial mass - Mass lost
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| 15 |
Considering the average crystallinity of PET fibers after treatment is 9.7%, what would be the crystallinity if the process conditions were unaltered but the drop distance doubled?
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9.7% |
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New crystallinity = Initial crystallinity + Change in crystallinity
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| 16 |
If the surface area to volume ratio of PET increased 15-fold due to processing, and the initial ratio was 0.1 mm²/mm³, what is the new ratio?
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1.5 cm²/cm³ |
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| 17 |
What is a major advantage of the melt fiber spinning system over traditional recycling methods?
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| 18 |
What does the term 'amorphous content' refer to in the context of PET recycling?
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The unstructured, non-crystalline state of PET |
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https://www.sciencedirect.com/science/article/pii/S2666821124000425
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| 19 |
What is the primary benefit of reducing the crystallinity of PET in recycling processes?
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It makes the PET more transparent. |
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https://www.sciencedirect.com/science/article/pii/S2666821124000425
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| 20 |
Which measurement technique was used to assess the polymer spectra to confirm the presence of PET?
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Fourier Transform Infrared Spectroscopy |
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https://www.sciencedirect.com/science/article/pii/S2666821124000425
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