ตรวจข้อสอบ > สิรินยา พาร์แฮม > Medical Science Aptitude Competition | Upper-secondary > Part 1 > ตรวจ

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A At equilibrium, Most inhibitors are able to bind to kinases. but some inhibitor molecule is able to dissociate from the kinase. B Some test compounds can alter the ATP binding site of the kinase. By binding to the allosteric region of the kinase which may be distant from Binding Sites C. This is because the capture sites are similar but not identical between kinases. A specific molecule can be developed for a particular kinase. D. In the presence of strong binding test compounds phage is attached to the test compound and is flushed to the end of the incubation. Therefore, the strong adhesion test compound produces low amounts in the plaque test

https://hmong.in.th/wiki/Molecular_biology_of_the_cell_(textbook) https://hmong.in.th/wiki/Protein-protein_interaction

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A. AFGP is active when R is hydrogen (H), so amino acids Residue binding to monosaccharides is not required for antifreeze action. B. Serine residues can form glycosidic bonds with disaccharides, but they There is no hydrophobic methyl group (-CH3), in this case Ra is H (see table). Therefore AFGP has no anti-discharge activity. C. If N-acetyl is replaced with -OH or O-acetyl, the activity of AFGP will be lost. D.DNA polymerase slippage may occur during replication and this results in the expansion of duplicate elements

https://www.si.mahidol.ac.th/department/biochemistry/home/MD/Lecture/Biochemistry_of_blood.pdf

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A .The rate of the protein synthesis is nonlinear with time (the graph is illustrate in the paper) B. The rate of protein synthesis can be obtained from the slope of line (the graph from A is used in finding answer B) This system synthesizes approximately 52,000 Daltons of protein each. 10 minutes or 5200 Daltons per minute which corresponds to approximately 47 amino acids per minute. C. The speed's movement of ribosomes along the mRNA is not constant. This is because there are a lot of separate stripes instead of a continuous fuzzy background. showed that there was a specific termination point based on the mRNA D.This is a discrete ensemble rather than a continuous fuzzy background. showed that there was a specific endpoint based on the mRNA, assumed where Ribosomes have to wait for the rare tRNA.

https://www.ncbi.nlm.nih.gov/books/NBK21054/

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A. The larger fraction that is not separated by protease is the transmission part of the protein Transmission parts are usually hydrophobic. B. The smaller fragments in lane 2 represent protruding protein domains. Outside the membrane, because the protein domain protruding outside the membrane is broken into shreds with protease C. It is the transmission part not the outside membrane part having a lot in leucine or isoleucine. Domain a binds to phosphate areas of the phospholipid, therefore it should have a lot in lysine. D.Proteases are too large to penetrate the cyst membrane.

https://sites.google.com/jarot.zya.me/bookshown5/pdfbook-download-cell-and-molecular-biology-concepts-and-experiments-by-gerald-karp http://www.cai.md.chula.ac.th/lesson/histology/unit01/plasma_membrane.htm

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1. Comparison of saltwater and freshwater The urine output changes slowly, decreases, and lasts longer (osmolarity fluctuations cause rapid death. The volume disrupts the output of the heart. so blood pressure which can be buffered for a while by releasing the blood vessels) 2. osmolarity as above Compare injections with drinking - general effects in the blood cause the maximum increase. 3.After drinking, there will be a few spikes. It is not caused by osmolarity or changes in the blood. This is the expected response before the fluid is absorbed. 4.After feeding the water from the fish Diluted urine is produced to remove it. and this is resolved by Y after isosmotic input. The urine will remain isosmotic.

https://www.sciencedirect.com/topics/neuroscience/cardiovascular-regulation#:~:text=Cardiovascular%20regulation%20depends%20on%20the,and%20cardiac%20rate%20and%20force.&text=This%20position%20within%20the%20artery,of%20blood%20from%20the%20heart.

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1 The exponential decrease after stopping the infusion. The definition of exponent is the rate of change proportional to the quantity. 2 This is because the filter media is concentrated in the urine by nephron. volume will decrease This causes the inulin to become more concentrated in the urine. But something else will spread back into the body ,so it will be hidden more slowly. 3. The filling and removal rate was 0.2 mol was given every minute and the concentration was 1.6 mol/L, so 0.2/1.6 = 0.125 L/min. 4. 25 moles is distributed in a volume which gives a concentration of 1.6 molar 25/1.6 = 15.6 L.

https://www.britannica.com/science/inulin https://www.researchgate.net/publication/49597010_Inulin_-_A_versatile_polysaccharide_with_multiple_pharmaceutical_and_food_chemical_uses

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1. Human fibers are more MYHI than in chimpanzees, which shrink more slowly. 2. Myosin can only produce a force for a short period of time. It binds and changes its structure in fast-moving fliaments. This transition is completed faster and a larger proportion of myosin is not bound. but will rotate back into position Imagine carrying a heavy load - you slow down and take small steps to spend more time with your feet on the ground. 3. MYHII fast cyclo Therefore, ATP is consumed faster and therefore requires a greater level of anaerobic glycolysis. This means that chimpanzees are less efficient and fatigue more quickly. 4.Humans are unusual ( only species known to have a predominance of MYHI fibers), reflecting the remarkable ability of humans to perform endurance activities. His ancestors were similar to chimpanzees. 5.Tension can be created by changing the structure to extract actin. So myosin works immediately. thus causing muscle fatigue even if it is not moving

https://www.nature.com/scitable/knowledge/physiological-ecology-13228161/ https://academic.oup.com/conphys/article/6/1/coy012/4931296 https://www.sciencedirect.com/topics/agricultural-and-biological-sciences/physiology

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1 DNA damage and other segmentation malfunctions activate P53, which can prevent the proliferation of damaged cells. or allow time to repair the damage. 2 There is no selection advantage for single-celled organisms to die. or entering a permanent state of cell cycle arrest. The primary role of P53 appears to be 'Genome guardian' in cancer-prone multicellular organisms 3. P53 is activated after translation. Therefore, more proteins do not change the rate of division until a problem arises. 4.P53 is activated after translation. Therefore, more proteins do not change the rate of division until a problem arises. 5.P53 is needed to drive stem cells to differentiate. and out of the cell cycle

https://www.ncbi.nlm.nih.gov/pmc/articles/PMC1550296/ https://pubmed.ncbi.nlm.nih.gov/8364108/#:~:text=The%20mechanism%20of%20functioning%20of,C%20circulating%20in%20the%20blood.

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1. Small molecules, only has H bonds, not covalent. 2.Y is compatible with the enzyme. Cause enzyme reactions, rationally increase the denaturation temperature. 3. Y has more H bonds than X (including pi-pi and hydrophobic stacking reactions). 4.If the substrate concentration is very high The active site may always be active and X prevails. The Z molecule does not bind to the active site.

https://www.sciencedirect.com/topics/biochemistry-genetics-and-molecular-biology/enzyme-property Enzyme - Wikipediahttps://en.wikipedia.org › wiki › Enzyme

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1 Alexis' grandmother had to have a mutation in order to pass it on to the grandchildren of the German Emperor. Therefore, there is a 50% chance that Alexis' mother will receive an affected X, and a 50% chance that Alexis will receive this X from his mother. So 0.5*0.5 = 25% 2.Victoria passed hemophilia to her multiple children. Therefore, the mutation must be present in many of her immature eggs. (Probably in one of the germ cells leading to her or during mitosis in her early germ cells) 3.Explain why it is inadequate

https://link.springer.com/referenceworkentry/10.1007%2F3-540-29623-9_7869#:~:text=Monogenic%20inheritance%20refers%20to%20the,or%20many%20non%2Dallelic%20genes. https://www.sciencedirect.com/topics/biochemistry-genetics-and-molecular-biology/enzyme-property

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A The vein are smaller then normal size so it is obvious that blood flow lower then normal B there is a hole between RA and LA this means boold flow back easily makeing a decrease in RV

C it is lower not higher in a reason of small vessle D ture because the vessle are bigger then normal causing it to increase as well

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A it can be see im the diagram

Tidal volume is the amount of air that moves in or out of the lungs with each respiratory cycle. It measures around 500 mL in an average healthy adult male and approximately 400 mL in a healthy female. The ventilation rate of a building, Q, is usually defined as the rate at which external air (fresh air) flows into the building.

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Phlorizin increased the absolute and fractional excretion of glucose, urine osmolality and negative free water clearance

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A. PCOS-related acne often flares on the lower face, including the jawline, chin, and upper neck. Although not a hard and fast rule, these areas are considered to be a hormonal pattern for acne. B.PCOS-related acne often flares on the lower face, including the j awline, chin, and upper neck. Although not a hard and fast rule, these areas are considered to be a hormonal pattern for acne.

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